解析Oracle查询和删除JOB的SQL

查询及删除重复记录的SQL语句

select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)delete from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) >

1)

and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)
注:rowid为oracle自带不用该.....
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录
delete from vitae a
where (a.peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
select * from vitae a
where (a.peopleId,seq having count(*)>1)

(二)

比方说
在A表中存在一个字段“name”，
而且不同记录之间的“name”值有可能会相同，
现在就是需要查询出在该表中的各记录之间，“name”值存在重复的项；
Select Name,Count(*) from A Group By Name Having Count(*) > 1
如果还查性别也相同大则如下:
Select Name,sex,Count(*) from A Group By Name,sex Having Count(*) > 1

(三)

declare @max integer,@id integer
declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >； 1
open cur_rows
fetch cur_rows into @id,@max
while @@fetch ......